haithar, universal gas law only applies if a hydrogen and oxygen and air gas mixture is considered an ideal gas
is it an ideal gas? i never ventured to determine if it was or not, yet...
some experiments could be done to compare it to steam, or air, and we have all the values from the steam tables and air tables, in the back of any thermodynamics textbook, they may be close but so far i think they will be slightly different
1 liter = 1 kg H20 = 1000 g H2O (because Density of Water = 1000 g/liter)
H = 1.01 g/mole (from periodic table) O = 16.00 g/mole (from periodic table) (mol or mole is just a number, or quantity, if you wanted to count all the atoms that make a gram)
H2O = 18.02 g/mol
1000 g H2O / 18.02 g/mol = 55.5 moles of H20
H2O ---> (1/2)O2 + H2 [balanced chemical equation, excluding energy input] 55.5 ---> (1/2)55.5 + 55.5 [moles] 1000 g ---> 27.7 moles*32.00 g/mole + 55.5 moles*2.02 g/mole [grams]
Thus...
1000 g H2O ---> 886.4 g O2 + 112.1 g H2 (rounded)
if you did this calculation for gasoline, then you would find water has about 2.5x the amount of hydrogen (by mass or volume, i am not sure, because 1 liter of gasoline does not have the same mass as 1 liter of water, gasoline is lighter than water) ... meaning [1000 g *?or?* 1 liter] of gasoline has 44.84 grams of Hydrogen
so we have the mass of the gas from the separated water, if you want volume you have to know the density
Volume = Mass / Density
your density depends on pressure, I don't have the figures for that
A rough figure I know of is that it expands 1860 times when separated, so 1 liter of water = 1860 liters of gas, i think at 1 atm pressure
if your cell has a fixed volume, then density will increase with pressure
the exact calculations ca be done, you just have to get the right figures to start with and determine exactly what your situation is, for what you want to find out
provide more information on your question and i can look up some more exact values and try and do the exact calculations...
Hardkrome, if you charge the cell, then drain the water, will it still have, say, 6 volts across the tubes? what can you say about the water being charged compared to the ss being charged?
in series resonance the voltage drops to that of the supply voltage across both the L and C, but you still have huge voltages across the L and C, which are out of phase, so they cancel out to give you the supply voltage across both of them
how do you move a massive amount of current? you need a large voltage, but voltage is measured from point to point, so you have to take into account exactly where you measure the voltage, and what is happening in between those points
impedance is lowest because the inductive reactance and capacitive reactance are equal and opposite - NOT because they are both zero... they are both large.
this happens because hydrogen is small, it is the smallest element, and it is smaller than the molecular gaps in metal, think of helium leaking through a rubber balloon after a few days, it's the same thing, it is worse for hydrogen under pressure, the hydrogen atoms get forced into the gaps in the metal atomic structure, and then they reduce the flexibility
it's like making steel out of iron, you heat up iron, and pound and hammer carbon into the iron, and it makes it stronger, but stronger is more brittle, and when you stick hydrogen in there, it is so tiny that it fills the small gaps, and therefore eliminates small movements and small flexes in the metal, so it becomes brittle
shouldn't be such a big deal for us running cars though, and in any case, well worth it to do so anyway
you could get a $120 signal/function generator and use that instead of Stans frequency generator, the use it to pulse your power electronics and then your coils
have you read all the patents yet? its easy to spend hundreds without a clear goal... i would also say start with 8xa, or rather start with much study
if you go to "resonant action" where particle impact is brought on by charged particles subject to voltage attenuation, the gasses will be jet propelled out of the resonant cavity and out of the water... would solve that problem...
komtek, if you are able to set it up so you have a pump forcing water through the cell, that will definitely break surface tension, and help move the hydrogen out.
By Kevin Wests method you mean pulsing a rewired (higher voltage) alternator?
Looks good!
Do you notice an increase in production from pulsing the alternator compared to not pulsing it? Are you finding an kind of resonance with your pulsing?
Still uses KOH and amps, only interesting thing is that is requires 0.37 volts, which may make it more electrically efficient than distilled water, but it says the CO2 reacts with the KOH, which means your KOH will soon be used up, which would make a constant supply of KOH needed... it's all dead end.