Back to Basics
Started by unknown · · 192 posts · last reply 16 December 2024
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#101 ·
One thing just occurred to me is that pulsing a transformer is equivalent to modulate its permeability
I mean with combining pulsing with impedance ransformation we get also impedance modulation...
At pulse start zero current maximum impedance
When pulse collapse current is maximum
Impedance is minimum when it takes the collapse pulse int
Than as current goes to zero impedance is modulated increasing after the pulse was dropped into the line
Just some thought passed here just now... -
#102 ·
I think a good way to start with this would be with antena coax cable.. maybe 20m is a good start
Just ad a termination and test to find resonance
Than measure the volts and amps in vs volts out on load...
If output voltage is higher than input you get the load with higher impedance than line
Adding a core may reduce the frequency and change this impedance of the cable
With this setup ready we can start making comparisons using a bifilar and go step after step knowing where you going -
#103 · date not recorded
Let us know how that works out for you. -
#104 · date not recorded
I did some of this tests already in the past like 6 years ago.. no need to do with more care measuring everything -
#105 ·
Check this out.
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#106 · date not recorded
Yes thats very interesting… and is the reason i believe we must keep the impedance of the bifilar really down to get power into the cell or to match to it.since the cell have ver low impedance… and even negative since is a capacitive load!
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#107 · date not recorded
The resistivity of the water is the issue and what needs to be matched to get maximum power across it. -
#108 ·
If match to water resistance it's what you want than you could manipulate the ppm until match for example...
Perhaps the impedance of the cell structure is not important as it's very short... only testing to tell -
#109 ·
Well, if you think about it, the water is the load on the DC circuit. Otherwise, like any other capacitor, it would just be an open circuit. -
#110 ·
Well, if you think about it, the water is the load on the DC circuit. Otherwise, like any other capacitor, it would just be an open circuit.
Thats true! the only part that i still have concern is that the interaction of the coils with the cell since the diode is on the other side should have an ac component..
If we think the cell as Open it will reflect the wave on the same polarity… raising the voltage in and reducing the current in (raise the impedance) (if applying unipolar pulse!!!)
the diode would actually block this reflected positive pulse trapping the wave between the bif coils and cell
on the other side if we take it as a short ckt (having lower impedance than line) it will reflect back the opposite polarity wave making the input hungry for amps (again in the unipolar case)… here the diode just allow more and more to go…
matching the impedance with the cell will make this reflections lower…
changing the ppm of the cell would change its resistance… so you can basically add drop by drop of some diluted acid on the cell and find where the cell have zero reflection…
in the video he talk about the electrons bunching up… just like meyers used to talk about…
something nice comeout of it is that not necessarily he wires need to be connected to have influence on each other… if you have a positive charge somewhere it will cause a charge redistribution… and voltage is electric field * d… so generating high charge density on both sides of the cell may also be a way to manipulate what is inside of it….
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#111 · date not recorded
This is how I see it.
1. As a DC circuit the impedance must be matched to maximize power transfer.
2. As an AC circuit at resonance to amplify the voltage that remains after the leakage of the DC current through the cell resistance.
This results in a step charging of impedance matched DC current on the cell. -
#112 · date not recorded
Have you ever done the simple resistance measurement of a single tube pair with your coils? Try this and see what you get.
Use a 5VDC power source. Put 2 coils in series on side and the third coil on the other side with the single tube pair at the ends. Know the resistance measurements of your coils first. I'm assuming they are likely between 70 to 80 like Stan Meyers. With the voltage on, measure the voltage and current (or calculate the current) on the coils and the tube pair in tap water. Calculate the resistance of the tube pair using V=IR. Sum the total resistance values of just the coils and compare to the calculated resistance of the tube pair in water.
See anything interesting? -
#113 · date not recorded
Is it filtered dc? How much ripple you have?
This can make a huge difference… also the internal resistance of the power supply should be taken into account…
Depending on how you are measuring you could maybe getting rid of the ripples using the coils reducing the peaks
Can you explain more? Or tell how much effect you could compare? -
#114 · date not recorded
Well, for mine, with calculations based on Meyers and Ronnie's, the sum of the resistances of the coils was near equal to the resistance of a tube pair in water. I don't think that's a coincidence. 🤔 -
#115 · date not recorded
As previously mentioned the water resistance must be equal to or higher than the resistance of the coils. This must be the case for any amount of voltage applied to it because water resistance changes with voltage applied.
Soooo....
You need to know the resistance of one of your tube pairs in water and what the maximum voltage that can be applied before the water resistance becomes lower than the total resistance of your coils.
And then of course build your coils accordingly.
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#116 ·
Make no sense for me… I tried connecting coil in series with the cell for years if you take careful reading you see that the resistance of water is proportional to the voltage aplied to it so if you want to get correct reading you will first need to make sure the voltage on water is equal to the other case including te wave form otherwise is not a fair comparison
That mean you need to apply two different voltages that imply also the source impedance may change
I could bet on it that you won’t get any difference provided the voltage waveform on the cell is the same regardless of the voltage applied
Exceto that if you give over 2kv because it will cause ionization and actually drop the resistance of water
There is nothing a coil can do to the current other than change its waveforms and cause voltage drop
Other than that a coil can do force like I explained on my recent posts -
#117 ·
Do the reading on straight unpulsed DC. This is how you impedance match the cell to the coils. You need to find the impedance match of the water with the coils with the maximum voltage you will apply to the primary of your transformer.
I have already done it. This will be how to get the maximum power transfer to your cell when then placing it on the Vic. -
#118 ·
Check my YouTube channel tomorrow you will see hopefully a demonstration of current being restricted and voltage taking over
I hope to be able to show the stepped up waveform with double frequency just like Stan show
No magic
I’m starting to think that those tube cells was only for comparison with.electrolysis
Remember who wins the war tell the story -
#119 ·
Do the reading on straight unpulsed DC. This is how you impedance match the cell to the coils. You need to find the impedance match of the water with the coils with the maximum voltage you will apply to the primary of your transformer.
I have already done it. This will be how to get the maximum power transfer to your cell when then placing it on the Vic.
Can you tell us what the efficiency was that you achieved?
cheers -
#120 · date not recorded
Check my YouTube channel tomorrow you will see hopefully a demonstration of current being restricted and voltage taking over
I hope to be able to show the stepped up waveform with double frequency just like Stan show
No magic
I’m starting to think that those tube cells was only for comparison with.electrolysis
Remember who wins the war tell the story
Who's at war? I've already done the wave form too. -
#121 · date not recorded
Check my YouTube channel tomorrow you will see hopefully a demonstration of current being restricted and voltage taking over
I hope to be able to show the stepped up waveform with double frequency just like Stan show
No magic
I’m starting to think that those tube cells was only for comparison with.electrolysis
Remember who wins the war tell the story
Who's at war? I've already done the wave form too.
I mean after Stan passed his stuff we’re only found years later and probably some of that stuff could be from someone who worked trying to make it work again for example … in my experience we will never know the true of what happen and how exactly he did.. so who wins the war tells the story stands for we know what they left us to know…
That said getting to the point the correct way of measuring the cell voltage would be using a resistor in series with it at least so you guarantee the voltage of the resistor is the same in both the situations… if in any way the voltage across the resistor plus cell is greater for same current flow than you can have some sort of effect
However I did it many times and found nothing I encourage you too look further
Now I’m into make the water work as the electron source… that for me is what will change its resistance
The whole process of electric polarization as I described on my thread not sure if you read it…
Im building a very nice setup so I can demonstra it well
I’m even thinking about using labview to plot the impedance curve of the cell in order to have a better understanding on how to improve it better
The way I would do it would be using a resistor in series and one in parallel with the cell as a divider
On labview than we can show the power the impedance whatever
The thing is a plot of voltage around the cavity resonating frequency
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#122 · date not recorded
Unfortunately due to significant health issues, I don't really actively work on this project anymore. Every once in a while I tinker with it.
Embora eu tenha aprendido português brasileiro nos últimos anos. 😂 -
#123 · date not recorded
Unfortunately due to significant health issues, I don't really actively work on this project anymore. Every once in a while a tinker with it.
Embora eu tenha aprendido português brasileiro nos últimos anos. 😂
Espero que esteja bem amigo! Também fiquei um tempão parado por vários motivos mas pude voltar finalmente para tentar provar minha teoria.
Da uma lida no outro thread e me diz o que acha da minha ideia de como isso funciona.
I wish you the best healing! Hope I can bring you hope!
Acho que finalmente faz sentido físico! -
#124 ·
Unfortunately due to significant health issues, I don't really actively work on this project anymore. Every once in a while a tinker with it.
Embora eu tenha aprendido português brasileiro nos últimos anos. 😂
health issues sucks.......
Hope you get well....
cheers! -
#125 ·
I know why the 2 chokes are different resistances. It's too catch when resonance falls due to gas fluctuations. It's a resonance range creating an alternating resonant frequency pulse.
Sounds plausible