The resistor in parallel with the diode would just help throwing away power so probably is in series with the diode isn´it?
this may serve to allow the fields to collapse based on the secondary coupling rather than the primary since the primary becomes a 80resistor. during switch off, assuming what i´m saying is correct;;
Switching diode (55) of Figure (3-22) not only acts as a blocking diode by preventing electrical "shorting" to secondary coil (52) during pulse off-time (69) of Figure (3-20) since diode (55) "only" conducts electrical energy in the direction of schematic arrow; but, also, and at the same time functions as a electronic switch which opens electrical circuit (60) during pulse offtime ... allowing magnetic fields of both inductor coils (56/57) to collapse ... forming pulse train (64a xxx 64n).
that could mean that at this point the cell is already positively charged and can't discharge into the secondary since it forms a open circuit...
collapse is a work for fast rate of decrease or just a synonym of decrease?
Steve i have only one regard about your flyback idea, the flyback generates high voltage during the pulse off, while stan says that diode stays like a switch in a open position during pulse off or i´m confusing it?
except your talking about having the chokes to receive the pulse... correct?
If you make a experimentation like inducing a flash back with the gas being sucked from the cell not pumped by it you will see than that it will explode because the speed of the gas will be too slow. How do you explain this? did you tried or can check this? Thats why i believe it have to do with the speed of the traveling gas.
the min size in my thoughts of each tube can be bigger depending on the pressure because you have anyway higher speed because of the pressure do you understand my point?
the min size second my thoughts of each tube can be bigger depending on the pressure because you have higher speed because of the pressure do you understand my point?
Do you agree whenever you want to pass 2,5 liters of gas per second you will need larger tubes ? I'm just proposing a mathematical thinking way to be able to adapt to any application.
Donaldwfc whenever you have a reduction in the size of the tubes you automatically need more pressure to pass the required amount of gas thru it all i'm saying is that the back flash don't happens because of the high speed the gas is traveling greater than the speed of burning. Of course if you dilute the gas with non combustible gasses you need less smaller holes because the speed of burning is lower so they can flow more slowly with no problem.We are dealing with at least 0,5 liter per second of gas up to 2,5 liters per second to run a car. Is like litz wire principle...
Is because it higher the speed of the gas output higher than the burning speed of the hydrogen. Stan said 350cm second So you just calculate from the amount of gas that must pass tru it and the pressure and orifice to know the speed it will flow into the tubes. Whenever the speed is small than that you are in trouble so you must calculate a minimum amount you would need to idle and than you just produce more and at a higher pressure whenever you need remember the cell produces its own pressure so no losses with pumps. The only thing you need is the solenoid to control gas input in the motor. another thing to consider is that you must remain at a pressure level that hydrogen wont explode.
I found an air flow calculator witch will calculate the velocity in meters per second of the gas exiting from a tube. You have to input the pressure the tube diameter and the amount of gas that should flow.
Yes and it agree with my thought because maybe after a first quenching from the cell that isolates it and a second after the mixing with non combustible gases, after this you can use thicker quenching circuit because the speed the gas need to travel is smaller. This explain the need for a pump for air and other for the ambient gases that he used.
I believe Stanley meyer told us about the speed of the explosion of the gas also in relation to his quenching circuit. I believe you must have the tubes thin enough to pass the gas from a gas source of a determined pressure at a speed higher than that of the burning speed of the oxygen and hydrogen. This way the flame can't come back. And the fuel with its oxidizer can travel safely. You just have to know the amount of the gas to pass thru it, it's density, the holes sizes and the pressure differential. I didn't found the calculation yet but is all about this. Even a 10-mm long Quenching circuit is enough to prevent the cell from explode if you determine your electronics to work in a manner as to maintain the pressure constant you can be 100% safe.
I discovered another mean for resonance... in quantum physics the electrons that bounds the molecules together move from molecule to other molecule all the time and this is also called resonance. Example you have a aromatic Hydrocarbon molecule witch is closed and witch have 3 double bounds and 3 single bounds, the electrons (cloud) in the bounds are known to change position inside the molecule all the time.
I was guessing today if stan was not meaning by resonance only the self ionization of water induced by voltage...
Hi outlawstc
He meant the resistance of the movement of the ion. As water have 10 electrons and all them are bounded there is no free electron to move.
the 78,54 is the dielectric constant, witch dictates the rate of electrons or coulombs of charge it need to hold to build up 1 volt.
The water molecule have 10 electrons and this is the reason why its so polar. As the oxygen aways want electrons this electrons get closer to him actually in its orbit and it leave the hydrogen as tips glued on him.
By holes i wanted to mean that when you have oxygen gas and you ionize it negatively you fill one of this two holes, lets say it start having 9 electrons instead of 8, thus every oxygen would want to link up with one hydrogen. Otherwise what i was trying to say also was that if you could instead ionize it positively lets say taking from it 1 electron making it have 7 instead of 8 electrons, it would like to link with 3 hydrogens, and this would lead to not reform water entirely as you see below.
Example (the extra oxygen come from atmosphere): If you take 2 moles of hydrogen and 1 mole of oxygen you have 1 mole of H20 Reforming water normally 18g per mole If you take 2 moles of hydrogen and 2 moles of oxygen you have 2 moles of OH- Reforming more water than H2 would normally happen 34g per mole of water If you take 3 moles of hydrogen and 1 mole of oxygen you have 1 mole of H3O+ Reforming less water than H2 would normally happen... 19g per mole of water Thus i guessed that what meyer intended by re energize the water was actually to allow the water to cool down and by action of the sun and the difference of the charges to bound together and rain again.
More things i learned:
Oxygen love electrons. Electrons or charge can't stay inside a conductor (tube) always outside. (i was thinking about how the delrin in the outside of the tube could influence in this) didn't concluded nothing yet. Neutrons exist inside the atoms to keep the protons from "touching"each other. And neutrons can be converted into 1 proton and 1 electron. Water have a certain +- 5% of deuterium witch is hydrogen with 1 neutron inside.
as far as i understand the engine vacuum only was used to draw air in...
stan used the pressure inside the cell as a mean to maintain stable production i mean enough gas to jump into the engine for accelerating, because the reaction on the cell was not instantaneous maybe at the time.
Psi is pounds per square inch that is different from BArs or atmospheres. If in one minute a space of 1 liter is compressed to 10 bar(145psi) you will have produced 9 liters of gas in one minute. Because the space was not in vacuum.