Dave
149 posts · 12 more in threads this archive does not carry · writing between Jan 2011 and Nov 2015
An identity on IonizationX as it was harvested, not an account on this site. Nobody here has claimed it, and nothing connects it to a person by name.
WFC VIC
#434 ·
So Tony W. is selling the VIC at globalkast, irondmax is at Stan meyers dream site and hydrogewaterfuel from Texas has one. TheHydrogenShop sells the microstar. So will somebody please post if they have got the VIC working, or haven't I looked enough. What about the seasoning process on the electrodes? Is that key? I want to cut the use of an electrolyzer and amperage on my conventional HHO kit under the hood. I want to make a high voltage type unit that fits under the hood of a modern vehicle, a tall task. I don't care if it is operating exactly at resonance or at max HHO production, just need a few lpm for combustion enhancement. plate designs fit well, cant get anything bigger than 3.5" anywhere. My first attempt is going to be using a lawton circuit, bought on at courtiestown.com.uk for about 75. Sucks how much retuning is needed on motor, big job, $$ too.
No one has gotten everything to work properly, and if they say they have they haven't proven it with data. What I mean is, there is no evidence that any hho has been produced in a different way other that that from electrolysis. The only reason to go in this direction is if you want to experiment with it and try to make it work. If your looking for something off the shelf that will give you results, using the vic and board is not for you. I'm just saying this so you understand the situation, don't let me stop you
First I would like to say, sorry for my lengthy absence. School is difficult and boring
I've been pondering electric fields ever since first starting this topic and a few days ago I came across something fascinating.
In my opinion, its ignored by physics because it proves simple laws incorrect and needs a lot of complex math to be proven other wise. That being said, I normally don't ever disagree with math but when it comes to the electric field and work, I just can't help it.
her is a clip from a website. I don't have the image, just imagine a closed loop with a static electric field
Let us now consider the special case where point A is identical with point B. In other words, the case in which we move the charge around a closed loop in the electric field. How much work must we perform in order to achieve this? It is, in fact, possible to prove, using rather high-powered mathematics, that the net work performed when a charge is moved around a closed loop in an electric field generated by fixed charges is zero. However, we do not need to be mathematical geniuses to appreciate that this is a sensible result. Suppose, for the sake of argument, that the net work performed when we take a charge around some closed loop in an electric field is non-zero. In other words, we lose energy every time we take the charge around the loop in one direction, but gain energy every time we take the charge around the loop in the opposite direction. This follows from Eq. (77), because when we switch the direction of circulation around the loop the electric field on the th path segment is unaffected, but, since the charge is moving along the segment in the opposite direction, , and, hence, . Let us choose to move the charge around the loop in the direction in which we gain energy. So, we move the charge once around the loop, and we gain a certain amount of energy in the process. Where does this energy come from? Let us consider the possibilities. Maybe the electric field of the movable charge does negative work on the fixed charges, so that the latter charges lose energy in order to compensate for the energy which we gain? But, the fixed charges cannot move, and so it is impossible to do work on them. Maybe the electric field loses energy in order to compensate for the energy which we gain? (Recall, from the previous section, that there is an energy associated with an electric field which fills space). But, all of the charges (i.e., the fixed charges and the movable charge) are in the same position before and after we take the movable charge around the loop, and so the electric field is the same before and after (since, by Coulomb's law, the electric field only depends on the positions and magnitudes of the charges), and, hence, the energy of the field must be the same before and after. Thus, we have a situation in which we take a charge around a closed loop in an electric field, and gain energy in the process, but nothing loses energy. In other words, the energy appears out of ``thin air,'' which clearly violates the first law of thermodynamics. The only way in which we can avoid this absurd conclusion is if we adopt the following rule:
The work done in taking a charge around a closed loop in an electric field generated by fixed charges is zero.
Hopefully that wasn't to long of a read. anyway, a static field can force and charged particle around a loop continually without performing work or using energy. Net work is zero because it would violate thermodynamics otherwise. Obviously, something is happening for nothing which isn't supposed to happen. According to thermodynamics no work is being done so if you were to harness this movement and create electricity, thermodynamics would not recognize it. Thats my opinion, and its really something cool to think about.
Nice theory.
But if an atom transmittes energy, then that will not go on forever, or am i wrong here?
Well it depends what is being transmitted. If I run a current through a gas I will produce a plasma that will emit photons until I remove the power supply. This is because the photons are being emitted when the electrons are moving to a lower energy level. That is what I think your talking about?
Now the awesome part. If i have a charged rod. A rod with a surplus of electrons. The rod cannot discharge without coming in contact with something conductive or at least something it can discharge through. So, if there is air or some other insulator between the charged object and ground or a discharged point it cannot discharge. But, it still has an effect on this objects its near. The photons I talked about are a force carrier, not a transfer of energy.
The photon is the force carrier for the electric force. It is in the upper right corner of the table bellow.
A charged rod will effect on electroscope by polarizing it. The rod is not discharging but for example if the rod was negative it would repel negative charges around it. Electrons in a conductor close bye would move as far away from the rod as possible. This would produce a polarized object. The charges in the influenced conductor will move until they get to a point of electrostatic equilibrium. But nothing is stopping me from applying the same fore to something else without recharging the rod.The rod will eventually discharge but it is not related to the objects it effects as long as it doesn't discharge into it by coming into contact with it. So, i can effect as many objects as I want without effecting the charge of the rod.
The force of the electric field is calculated by E=Kq'/(R squared) and the electric force is calculated between to charged objects by F=Kqq'/(R squared) Everything is in absolute value.
I'm sure you guys have seen these equations before but if anyone needs more info I can explain them further.
Sometimes its hard for me to understand what others are talking about so I understand if I need to explain my points of view better. Just let me know.
For the first time in quantum mechanics and electrostatics I was introduced to an event when energy is created (they think). Its very simple and related to what we're working on.
A charged object has an effect on its surroundings. We all know this from seeing and doing experiments with static electricity and a stream of water. The charged object bends the stream of water but does not lose its charge. How could this be? The electric field is the answer. A static electric field emits photons without discharging and these photons influence the things around it. Work is done for free

Photons are the force carrier.
I tried taking the output of a MOT and rectifying it and then connecting one lead to ground and the positive to the grid, nothing happened. No amp flow. After doing it, I realized it just doesn't make sense electrically speaking. I think this guy was right.
I'm not sure the electron emitter is the answer either. If no current flows, the bulb will not get hot and will not emit electrons creating the void to be filled.
ionized HHO
#41 ·
I don't know to much about nuclear forces. Hopefully I will revisit this paper further down the road in my education.
What is this universal energy path he is talking about?
This paper differs from much of his other writings. He described a lot more happening to the nuclei.
ionized HHO
#25 ·
Has anyone ever looked into tunnel ionization? it seems that its not restricted by classical physics.
Exciting water mist
#1 ·
In lab we were identifying substances by the wavelength they give off when electrons are pushed to a higher energy state and then return to ground state. For practice, we used excited water vapor! It looked just like a neon light. The power supply was only 5kv ac. I don't know if this thread will go anywhere but i thought it was cool!
Static electricity
#10 ·
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I'm not sure what you are referring to as normal electricity? A static field is a static field, just generated in different ways.
And that brings me to my next question, are you guys talking about using natural static electricity from rubbing stuff together or generating a static electric field like in the video above?
End of the Meyer story?
#13 ·
Anyway, In Stan's patents, he never claimed a free energy device, just an affordable and economic way. Is it possible that he solve the problem of using tap water with applying more voltage and controlling it through impedance. It's not efficient but it gets the job done. Once you have hho you no longer have to break bonds but only make ions. I've stumped my friends and proffesors with this one. Apparently there isn't a lot of research on ion ignition. As you can see from the latest video, Stans hydrogen cell was not the only thing involved : )
Hydrogen gas gun
#34 ·
Here is a link for an update video that I made. Almost testing time : )
Hydrogen gas gun
#33 ·
ps. thanks everyone for the helpful ideas
Hydrogen gas gun
#32 ·
I've got pretty much everything together except the out tube which needs a slit cut in it. I'm pretty happy with how it's coming together. I'll post some stuff as soon as I'm happy with it. I've also just started on my simplified electron electron circuit. Hopfully it works : )
Hydrogen gas gun
#29 ·
He's a good guy!
Hydrogen gas gun
#27 ·
Hydrogen gas gun
#25 ·
whenever you feel the need to play the bad guy, go ahead and do it

I'm here to learn and get advice. And of course help with what I can.
Your a very knowledgeable guy and i value your input!
The vacuum seems to have more than one benefit.
1) better ionization!
2) less chance of explosion!
3) Hho going from pressure to vacuum increases kinetic energy!
So, this is getting more complex haha, I'll put it under vacuum using an old compressor from something
I just picked up xenon and another uv light for testing
