End of the Meyer story?
Started by unknown · · 21 posts · last reply 16 July 2012
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#1 · date not recorded
The story of Meyer, as we know it, might end here.
Breaking a covalent bond absorbs energy, as energy is required to break the bond - the energy is absorbed when the bonds are broken.
So breaking a bond without energy is simply not possible........
Any reaction from you outthere?
Steve -
#2 · date not recorded
Isn't this why we are applying energy to the cell?
TS -
#3 ·
Only volts?
No electrons?
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#4 ·
have you built all Stan's tech acording to specs and does not work?i don't think so! you discredit his tech only by a theory http://www.youtube.com/watch?v=JvxvHLh-k5k&feature=plcp
if the guy had a proper transformer hidrogen will be pouring out of those pipes,he has only 800 wraps in total or so,Stans transformer should have aprox. 10000 wraps,so we must keep trying and replicate at least John experiment,and then came up with theories... -
#5 · date not recorded
The big problem about stan stuff is that he didn't explained where the technology came from. Thereto became impossible for people to really understand what he did. However when he meant "for those with knowledge in the prior art will be evident" he was not joking. Quantum mechanics explain this possibility. There is energy anywhere, since we are not at absolute 0K temperature. The thing is how to use this energy, how to create the conditions required for hydrogen to be generated.
Anyone was able to replicate stan stuff yet because all want to copy his designs and not understand why he did that things. The great problem arise when you get a really advanced system and want to simply make it work out of nothing. It simply does not work that way.
Any collection of charges has an electric field associated with it and this electric field can deflect electrons, and since there is no electron flow within this electric field frame because is not a dipole no energy is consumed.
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#6 · date not recorded
have you built all Stan's tech acording to specs and does not work?i don't think so! you discredit his tech only by a theory http://www.youtube.com/watch?v=JvxvHLh-k5k&feature=plcp
if the guy had a proper transformer hidrogen will be pouring out of those pipes,he has only 800 wraps in total or so,Stans transformer should have aprox. 10000 wraps,so we must keep trying and replicate at least John experiment,and then came up with theories...
Dont understand me wrong, but i didnt have seen any working replication of Meyer, yet.
So, i dropped the question, if we are not chasing ghosts here........
I have made several attempts. Created the nicest scopeshots.
But still not one indication that there was a more efficient way of creating hydrogen.
Still i hope to be wrong and we succeed in cracking Meyers patents.
Steve
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#7 · date not recorded
Why would you assume the process requires no current? I don't recall Meyer ever stating such a thing. Less current than normal electrolysis is what I have always understood. In my opinion, his technology works just as described. My replications work just as his did and I have seen many others on this forum alone do the same. If your able to run a cell for a long period of time, such as 45 minutes to an hour, with little or no heating of the water, would you not call that a successful replication? -
#8 · date not recorded
No way, No heating can only mean that the production of gas is low, it became over unity if the gas output is over unity. Of course if the gas output is over unity and the temperature don't raise than you got what stan had...
I didn't wanted to mean no current is used i just meant that the electric field being applied differ somehow of a dipole field... Of course there are losses so the current will do flow to a certain degree. The fact is that as it is restricted it allows voltage potential to take over and do the work, in the dead short condition.
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#9 · date not recorded
Over Unity? Who said anything about over unity? Certainly Meyer never did. In fact, he had stated several times his devices were not. I get the feeling the desire for mystery overshadows the need for truth.
Tell me... Does this look like low gas production?
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#10 · date not recorded
Who can say that, at leat only looking is impossible. Now if you look the dune buggy demonstration video and you notice the cell you see he is really using Gas and lots of it. not just the white stuff..
Stan clearly stated is overunity because over unity means produce more power out than in, what he also said is that thermodynamic law conserve energy and that the water is the energy source, and also said that the conservation of energy do is not defined by power input power output.
I can only deal with numbers, if the guy is producting more than 33 liters of gas spending less than 66 watts its overunity. -
#11 · date not recorded
Who can say that, at leat only looking is impossible. Now if you look the dune buggy demonstration video and you notice the cell you see he is really using Gas and lots of it. not just the white stuff..
I know english is not your native language, but that is a contradicting statement. I'm not sure what the "white stuff" has to do with any of this. I have actually tested my cell as Stan did in his video with several different motors and engines to run idle. Cold starts were really the only hurdle I had to get over. The amount of gases produced was never the issue, it was always a mixture problem. And when throttling was achieved the ICE's still lacked power and torque. Humidity was also an issue at times.
Fabio, how well educated are you in the art of ICE's? Do you have access to any small motors or engines that you can tinker with? Do you think it would be beyond your skills to rebuild a small junked motor? -
#12 · date not recorded
Sorry my english might not be really good because i'm autodidact. By the white stuff I meant the small bubbles... At the buggy first run demonstration you clearly see the water bath boiling very vigorously, not just small tiny bubbles...
I like ICEs since i was 10 years old, i use to dismount and mount it again... Now i got a better figure of its operation since i studied thermodynamics recently at the university and since today i know a lot about sensors and timing and synchronization mechanisms.
I never got any ICE at hands to play with hydrogen, but i read about a lot and saw many people doing it, so i know you don't really need lot of gas to run it lean, however as you just stated it will lack power because you are limited to the battery energy.
If i achieve my goal, to create all the control electronic metering mixing and injecting system will be really easy...
Since i could never generate as much gas as 60liter per minute or at least 30L yet with just few watts, I would not go to work on engines yet.. . _Because there will be even more problems to solve. Of course i would be able to try the gas processor, but that really is not my focus now.
I imagine that if you add some gasoline to the water will help you start the engine and also let you run partly on water, but what is the point if your consuming more energy to generate the gas than it is giving up inside the engine?
Thats why my focus is exclusively to generate loads of gas. -
#13 ·
I agree, with both Steve and Sebs. Steve, you are right in pointing this out. This is why we are bound by thermodynamics. You can't just get something from nothing and that's clasicsl phisics. As far a quantum mechanics, what's Sebs is taking about. The unknown! Thngs we don't understand. Tunnel ionization for example. It's different, classical physics doesn't ecnologe it.
Anyway, In Stan's patents, he never claimed a free energy device, just an affordable and economic way. Is it possible that he solve the problem of using tap water with applying more voltage and controlling it through impedance. It's not efficient but it gets the job done. Once you have hho you no longer have to break bonds but only make ions. I've stumped my friends and proffesors with this one. Apparently there isn't a lot of research on ion ignition. As you can see from the latest video, Stans hydrogen cell was not the only thing involved : ) -
#14 · date not recorded
In the 1993 Denver presentation, Stan indicates that energy is not being created. In a fusion device only small amounts of energy are utilized to release the tremendous amounts of energy within the nucleus. In a similar manner, relatively small amounts of energy are used to force electrons into higher energy orbitals and when these highly energized molecules have the colvalent bonds broken, a tremendous amount of energy is ulimately released -
#15 · date not recorded
well, people are telling me that energy is never consumed.
Its there. Its changes shapes or form, but its there.
So, you tell me.....
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#16 · date not recorded
How much energy does it really absorb when the bond is broken? In simple electrolysis, electrons are not absorbed to make Hho, electrons simply have to pass through the water. What energy is being absorbed?
Stan heated the water with the steam resonator, this heat energy would be available for absorption after the bond is broken with potential. -
#17 · date not recorded
In water, the charge is passed thru by ions.No flow of electrons, as far as i have understand it.
Nice theory about the use of the steam resonator.
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#18 · date not recorded
The greater problem is the oxygen atom release the electron. The heat interacts quantum mechanically. The heat raise the possibility for an electron to be ionized with a lower potential than was theoretically predicted as a minimum. The heat increase the speed water molecules vibrates..
No electron can effectively cross the water, actually the electron makes its run only around the circuit... in the water only ions move.
Stan might have tried to pass the electron thru the water to create avalanche effect.
you need for electrolysis two electrons with at least 1,24 ev... for it to happen i guess
For the record for a photoelectric effect to happen the electron or photon must strike the electrode with an energy greater than the work function... -
#19 · date not recorded
In the 1993 Denver presentation, Stan indicates that energy is not being created. In a fusion device only small amounts of energy are utilized to release the tremendous amounts of energy within the nucleus. In a similar manner, relatively small amounts of energy are used to force electrons into higher energy orbitals and when these highly energized molecules have the colvalent bonds broken, a tremendous amount of energy is ulimately released
Interesting! I bet I know of a simple experiment to prove this.! Thanks jim!
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#20 ·
Here is another video very closely related to the topic at hand...
http://www.youtube.com/watch?v=F4I5mgBKPZY&feature=g-vrec -
#21 ·
I think I scanned this whole thread pretty thoroughly and its a surprise that it is started by an administrator of the site dedicated to replication of Stan Meyer technology. Odd also that I saw no mention of tapping zero point energy by the high voltage oscillation of the VIC. Keep in mind folks that it is likely that the circuit is like a sail boat putting up a sail to catch the teaming etheric winds of charged electromagnetic particles put out by the sun that Nikolai Tesla harvested. It is not a closed thermodynamic system subject to the second law. It does not create energy over and above what is put into it, it harvests the extra energy from the ether. According to modern physics particle theory, there is no ether, quoting the Mikelson-Morely experiment of about 1909?, or so. As if science should stand still for so long... But to be completely submerged into conspiracy theory, a must-read is "The Secrets of Anti-gravity Propulsion" by Paul LaViolette, or the "The Hunt for Zero Point Energy" by Nick Cook. Then you start to suspect our universities are languishing in ignorance and teaching inferior scientific theory, possibly for many reasons...
Regarding timeshell's progress on this topic, he should try this:
check P J Kelly's Free Energy Guide, Ch. 10, . I'm guessing it could be the need to season the electrodes.
I guess I can't post more than twice a night?
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