function of VIC: rethinking signals...

#1 · date not recorded

actually this question is to get dynodons response:

is it possible that the secondary was less turns than the primary?

Steve meyer says in a radio interview that it only takes 11 volts to pull an electron from hydrogen.

if the primary has 60 volts at 600 turns, and the secondary has 20 volts at 200 turns, then 1 amp at the primary should equal 10 amps at the secondary

now with such a strong 20 volt signal and such a high amperage on the secondary, the magnetic flux is greatly increased in the core and the amp restriction is very high in the chokes at resonance...with the 20 volts passing through to the wfc waveguide..and a very high magnetic field at the chokes... a very strong opposition to current flow past the chokes...

thinking outside the box... were the drawings misleading?

i really dont think so, but its worth a try.
any comments from others ?

Steve

#2 · date not recorded

Good questions again.

I suggest you read up on Rutherford–Bohr. Losing electrons happens by use of adding energy.
Normally, that would be photonic energy and you measure that in eV like with LEDS.
The ground state energy level of the electron in a hydrogen atom is −13.6 eV
Hydrogen's ionisation energy is 1312 kJ mol-1
I am pretty sure that Steve Meyer ment this and not normal 11V stuff......

http://en.wikipedia.org/wiki/Bohr_model

http://en.wikipedia.org/wiki/Hydrogen

http://www.chemguide.co.uk/atoms/properties/hspectrum.html

Steve

Dynodon

#3 · date not recorded

Ali,as you can clearly see in the pictures of the coil packs,the secondary coil is alot larger than the primary.It is also evident in the readings taken of the coils as well.All of the coils were traced out to their connections.
Don

Minde

#4 · date not recorded

@All

Hey guys

@Ali

The main point at Stans 3-23 was that he was using relatively small AWG 29 copper wire.
AWG 29 = no more than 0.5-2 amps... My primary AWG 22 heats up a lot from 2 amps so AWG 29 should pass even less...

"Stanley: ....so voltage can take over and perform in dead short conditions...." How can voltage can perform in dead short conditions - wich is what we get in water capacitor - almost dead short. Then how can voltage perform in dead short with no amps... should be dissipated immediately in other words overhelmed by the losses if you will. Mystery to me.

Minde

pakakezu

#5 · 31 Jan 2012

What if one of the tubes were insulated? By some kind of surface oxidization or other materials. In this way we really have a water capacitor, but we need strong electrostatic field between the tubes, this means high voltage, to can pull away the molecule.

hydrogenmask

#6 · 31 Jan 2012

Hi Ali
interesting rethinking.
why does meyer chooses the MUR1560 diode (600v 15A) .Why such high current rating ?
However then as Minde said why does he uses awg29 wire that is good for a maximum of an amp or so?
These 2 question contradict each self.

TonyWoodside

#7 · 31 Jan 2012

Stephen Meyer is referring to 11eV, not 11v

Bubz

#8 · 31 Jan 2012

Yes! Let the voltage do the work! Not the potential voltage between the exciters, but the eV(electron volts).

Quote

In physics, the electron volt (symbol eV; also written electronvolt[1][2]) is a unit of energy equal to approximately 1.602×10−19 joule (symbol J). By definition, it is the amount of energy gained by the charge of a single electron moved across an electric potential difference of one volt. Thus it is 1 volt (1 joule per coulomb, 1 J/C) multiplied by the electron charge (1 e, or 1.602176565(35)×10−19 C). Therefore, one electron volt is equal to 1.602176565(35)×10−19 J.[3] Historically, the electron volt was devised as a standard unit of measure through its usefulness in electrostatic particle accelerator sciences because a particle with charge q has an energy E=qV after passing through the potential V; if q is quoted in integer units of the elementary charge and the terminal bias in volts, one gets an energy in eV.

The electron volt is not an SI unit and its value must be obtained experimentally.[4] Like the elementary charge on which it is based, it is not an independent quantity but is equal to (1 J/C)(2 h α / μ0 c0)0.5 It is a common unit of energy within physics, widely used in solid state, atomic, nuclear, and particle physics. It is commonly used with the SI prefixes milli-, kilo-, mega-, giga-, tera-, or peta- (meV, keV, MeV, GeV, TeV and PeV respectively). Thus meV stands for milli-electron volt.

Atomic properties like the ionization energy are often quoted in electron volts.

In chemistry, it is often useful to have the molar equivalent, that is the energy that would be produced by one mole of charge (6.02214129(27)×1023) passing through a potential difference of one volt. This is equal to 96.4853365(21) kJ/mol.[3]

Quote

13.6 eV: The energy required to ionize atomic hydrogen. Molecular bond energies are on the order of one eV per molecule.

webmug

#9 · date not recorded

Quote from: Minde on January 31, 2012, 00:40:24 am

@All

Hey guys

@Ali

The main point at Stans 3-23 was that he was using relatively small AWG 29 copper wire.
AWG 29 = no more than 0.5-2 amps... My primary AWG 22 heats up a lot from 2 amps so AWG 29 should pass even less...

"Stanley: ....so voltage can take over and perform in dead short conditions...." How can voltage can perform in dead short conditions - wich is what we get in water capacitor - almost dead short. Then how can voltage perform in dead short with no amps... should be dissipated immediately in other words overhelmed by the losses if you will. Mystery to me.

Minde

Hi,

" how can voltage perform in dead short with no amps"

If we charge the plates (electrostatic) then the electrons path in the water molecule would elongate.
If this path is wide enough then the covalent bonding of water molecule snaps and the atoms would regain free floating electrons to be stabilized.
This splitting or pulling apart is possible because the water molecule has low bonding forces.
Voltage can preform work it has split the water molecule with no current. Current is restricted, it can not flow, because the breakdown is prevented we are having high resistance in the chokes on resonance.

If this restricting is not possible, the current can flow and we couldn't elongate the electron path enough. They slip through our capacitor (flowing) to the other side and the process repeats.

Br,
Webmug

ali

#10 · date not recorded

Quote from: webmug on January 31, 2012, 14:18:28 pm

Hi,

" how can voltage perform in dead short with no amps"

If we charge the plates (electrostatic) then the electrons path in the water molecule would elongate.
If this path is wide enough then the covalent bonding of water molecule snaps and the atoms would regain free floating electrons to be stabilized.
This splitting or pulling apart is possible because the water molecule has low bonding forces.
Voltage can preform work it has split the water molecule with no current. Current is restricted, it can not flow, because the breakdown is prevented we are having high resistance in the chokes on resonance.

If this restricting is not possible, the current can flow and we couldn't elongate the electron path enough. They slip through our capacitor (flowing) to the other side and the process repeats.

Br,
Webmug

exactly

THE RESONANT CIRCUIT IS NOT A PARALLEL OR SERIES TANK CIRCUIT LIKE IN THE COMMON AC TANK CIRCUITS

WE ARE NOT USING AC VOLTAGE

LOOK AT THE FORMULA IN THE FIRST FEW PAGES OF STANS FULL DATA PATENT FOR RESONANCE

THE SECRET IS THAT THE CHOKES MUST BE WOUND WITH THE WIRES SEPERATED AND WITH A LAYER OF PLASTIC TRANSFORMER TAPE BETWEEN EACH LAYER TO INCREASE THE CAPACITANCE OF THE CHOKE

SO THE FREQUENCY MUST RESONATE WITH THE ACTUAL CHOKE COIL'S CAPACITANCE AND INDUCTANCE TO CAUSE HIGH VOLTS AND LOW AMPS, ALMOST ZERO AMPS...THAT IS THE PURPOSE OF THE RESONANT SCANNING CIRCUIT. IT FOLLOWS THE CHOKE COILS RESONANT FREQUENCY BASED ON FEEDBACK FROM THE PICKUP COIL

THE REASON THE SCANNING CIRCUIT IS USED IS BECAUSE THE FREQUENCY WILL GO OUT OF RESONANCE AS HYDROGEN AND OXYGEN ARE DISASSOCIATED IN THE TUBE SET AT VARIOUS LEVELS AND AMOUNTS

THE VIC COIL IS DESIGNED WITH ITS ASSOCIATED CIRCUITRY TO KEEP THE CHOKES AT MAXIMUM AMP RESTRICTION WHILE ADAPTING TO THE NEEDS OF THE WATER FUEL CELL

THEREFORE BOTH CHOKES MUST MATCH EXACTLY

newer technology explained:

LATER ON STAN WENT TO A DIFFERENT STYLE OF VIC COIL (slotted tesla style windings) BECAUSE HE WAS PROCESSING A WATER VAPOR, THE DEMAND DID NOT CHANGE IN THE INJECTOR AS IT DOES IN THE WATER FUEL CELL TUBES BECAUSE WATER VAPOR / GAS HAS A FIXED CAPACITANCE IN THE INJECTOR, no need to follow the resonance of the chokes...

ALSO THE DISTROBUTOR HAD NO ROTOR AND NO Traditional ignition coil

the injector solenoids were timed to deliver fuel just before top dead center at 125 psi through a check valve, the newer vic coil delivered a pulse train to the injector after top dead center and the water fuel exploded instantly

HERE IS MY LATEST VIC CIRCUIT SIMPLIFIED.....USE PCB EXPRESS SOFTWARE TO VIEW

PCBExpress_VicCircuit_simplified.sch

TonyWoodside

#11 · 2 Feb 2012

This is the DC analysis for the Driver Circuit with the 43mH Primary coil.

(http://www.globalkast.com/images/tonywoodside/DC_Current_Analysis.png)

Newguy

#12 · 2 Feb 2012

"Steve meyer says in a radio interview that it only takes 11 volts to pull an electron from hydrogen."

What exactly is the purpose of pulling an electron from a hydrogen what(atom,molecule,compound) ? To pull implies an attraction force wich for an electron would be a possitive force it seems alltho a hydrogen atom is obviously positive by nature or neutral in molecular form right?
I think he kinda mentioned it was thought to take 13v to do that before...
How do we accelerate an electron or pass it thru a potential diffrence of 11v to gain 11v for this pulling action and where does it go? Does it saturate in the water waiting to link up with an atom missing an electron we just pulled it from or is it used up some other way?

Its interesting to know also that it takes a 1,836g magnetic field to flip the spins of a protons electron in a glass of water.

Im wandering now if its possible to flip the spins of those electrons in that band Steve Meyers was talking about???

TonyWoodside

#13 · 2 Feb 2012

I also want to point this out, not sure if anybody has paid this much attention.

(http://www.globalkast.com/images/stanmeyer/VIC_Analysis.png)

HMS-776

#14 · 3 Feb 2012

Yeah, I'm pretty sure those numbers are for the Injector VIC coil.
There's lots of good info in the appendix section of the TB.

Back to that injector VIC.....

Transformers are typically made so that no empty space exists (wire completly fills all the cavities/bobbins)

I calculated what the turns ratio would be if each cavity were completly filled.

Result: 400 turn primary, secondary coils (secondary + chokes) came up to 11,956 turns. (chokes completly filled cavities and turned out to 11.6K Ohms ea)
Turns ratio 1:29.89
12V input 358V out
Note that these calculations will not be exact in the real world, but they shoudl be fairly close.

I think the injector VIC used a lower frequency gate pulse to allow the voltage to build up higher (Up to 40kV)
Or this VIC operated as a flyback: Voltage comes from fast rate of current change from square wave

(http://i642.photobucket.com/albums/uu141/Hms-776/vicc.jpg)