timeshell

Have you ever done the simple resistance measurement of a single tube pair with your coils?  Try this and see what you get.

Use a 5VDC power source.  Put 2 coils in series on side and the third coil on the other side with the single tube pair at the ends.  Know the resistance measurements of your coils first.  I'm assuming they are likely between 70 to 80 like Stan Meyers.  With the voltage on, measure the voltage and current (or calculate the current) on the coils and the tube pair in tap water.  Calculate the resistance of the tube pair using V=IR.  Sum the total resistance values of just the coils and compare to the calculated resistance of the tube pair in water.

See anything interesting?

This is how I see it.

1.  As a DC circuit the impedance must be matched to maximize power transfer.
2.  As an AC circuit at resonance to amplify the voltage that remains after the leakage of the DC current through the cell resistance.

This results in a step charging of impedance matched DC current on the cell.

The resistivity of the water is the issue and what needs to be matched to get maximum power across it.

Let us know how that works out for you.

Why not use solder designed for stainless steel?  That's what I did.

Well, my new setup uses 316 wire connected directly to the cell.  We shall see.

Personally, however, that doesn't make sense to me.  The gas flow is too substancial, like there is still an electric force acting on it.

The pipes are 304 and 316L.  You can see the bubbles coming off the alligator clips too.

I really am not sure I can agree with that.  This ran for hours afterwards like this.

https://youtu.be/x7r42hEmFrU?feature=shared

When I made this video years ago, I was using a circuit that was similar to the VIC, but without the chokes.  It has only just occurred to me now that this is what I am now describing with the secondary resistance being less than the water.  The secondary that was being used for this had multiple wire stands in parallel of 24 gauge wire of only 100 turns (resulting in very low impedance), 1:1 ratio with the primary. But you see the result?  I was able to put a charge on the cell that stayed after power was turned off and produced gas from that residual charge.

The driving circuit I used was very simple and automatically tuned to the resonant frequency of the secondary and cell.

Meyer also said KISS.

Why are you talking about 20A??  The whole point of this project is to use pure voltage and low current.  The wire on the secondary would immediately melt with that much current.  It completely defeats the whole idea that this project is about.

Also, I said let's re-examine what he says.  I'm not sure if he knew completely what was going on, or the best way to explain it, but we can examine what his perceived results were and see how it applies to the actual circuit design.

Now, considering all this, let's re-examine what Mr Ronnie said 7 years ago:

https://open-source-energy.org/?PHPSESSID=bm6nh49ovnsc5b7ct68tu1n3ml;topic=2785.0

The time has come to tell my story how Stan Meyers Fuel Cell Works. October the 23th 2016

First! I want to have a disclaimer statement. I Ronnie Walker will not be responsible for anyone that uses this information in this thread to create any type of voltage and current either high or low of either of the two. You take full responsibility of your own actions and the use of any information that is discussed in this thread. "High Voltage and Current can KILL You" This thread, and the post in this thread made by me or others, is for information use only.

Second! It is assumed that anyone that uses this information has at least the basic knowledge of electronics, formulas and equations. Therefor I will not be held responsible for anyone that uses this information, and can not get a Fuel Cell to work.
In other words DON'T BLAME ME!

Thanks,
Ronnie Walker (gpssonar)


Let's get started! (October 23, 2016)

Several years back I made the discovery how Stan was able to produce gas on demand for the second time. Like everyone else I keep throwing voltage to the water hoping to see it just fall apart into Hydrogen and Oxygen with no luck at all.
Like everyone else, with very little production of the two gases. (Due to Amp Leakage)

I came across a drawing in Stan's Tech Brief that clearly shows their is amp leakage in the cell. (Which I will Post below)
Like everyone else, I thought the resonant reaction Stan talked about, was on the water itself.
When in fact the resonate action will only take place when the water is removed from within the cells.
Then an only then will the two choke coils come together and interact with one another.
As long as there is water between the cells, the two choke coils will not interact with each other which will stop any resonance to occur between the two due to the dead short. (Water)

Stan states, that you must overcome the dead short condition before resonance will occur and allow the voltage to take over and do the work.
This is were everyone including me took this statement way out of context.
It dose not mean applying a high voltage to the water and it will just go away.
It means removing the water within the cells, which is a dead short condition in order to over come it.

So the question is how do we remove the dead short condition so the coils can interact with one another?
The answer is Amp leakage within the cell.
So how do we create this Amp leakage in the cell?
The answer is with the L1 Choke Inductive Reactance and the Cell Capacitance Reactance.
When you design the choke and the cell it has to meet certain criteria.
When you subtract the two from one another you don't want the math to come out to zero.
What you want is a ohm value left over. That ohm value is what is going to cause the Amp leakage within the cell.
This is where you get into voltage leading the current or voltage lagging the current, depending on if the net value of ohms is capacitive or inductive.

So in other words as the voltage increases so does the amp leakage.
At a certain point of increased voltage the water will be remove from the cell and will be replace with gas.
This is where the resonate reaction will occur between the two chokes and the voltage will take off to infinity and the amps will drop to nearly nothing. (Voltage taking over and doing the work). Since all coils are adding one another.

In the drawing I have colored it showing the water in blue and gas in yellow.
As you can see there is amp leakage that causes the water to be removed and replaced with gas or gasses.
Once this is achieved and only when this is achieve is when you will see a resonate condition take place to make Stan Meyers Water Fuel Gas on Demand.

Further, it's important to keep in mind that the water resistivity in your circuit will be also influenced by the number of cells (pipe pairs) and how much electrical leakage there is between your individual cells (pipe pairs).  Electrical leakage will reduce the sum of the resistivity of your cells (pipe pairs).  Better isolation of your cells (pipe pairs) should result in higher resistivity.

So, with keeping the above in mind, these are 2 critical design elements to keep in mind in the design of your circuit.

1.  Resonance.
2.  At resonance, the circuit is purely resistive and the water is a purely resistive element that must be impedance matched to the source 
Remember, all 3 coils will contribute to resistance at resonance and should be matched to the water impedance.

Need to remember this is a variable circuit.  Need to start with low voltage and low frequency with the water, moving to high voltage and high frequency as more gases create"air".  From one side to the other, we want the most voltage and power across the cell.  Therefore, the source impedance cannot exceed the impedance of the cell.  Otherwise more current will flow across the cell. So the circuit must start low and continually be tuned accordingly until the result is achieved.

There you go.

So, if the water resistivity of your cell is 50 ohm, then your secondary needs to be less than 50ohm.

The water has to be able to resist current flow.  The only way that can happen is if the resistivity of the water is greater than the resistance of the power source, in this case the secondary.  The secondary needs to be tuned as close as possible to the resistivity of the water without going over to maximize impedance matching, but without going over the resistivity of the water itself.

I believe Meyer used this gated pulse to control… however from what I’m seeing about how the pll works and how the Q factor should be and how much it can get out of resonance all the time… summed with the patent pll info… I would say the gate must be much longer otherwise it won’t be able to lock if is to few pulses!

I believe the gate period must by at least as long as the sweep or longer

Also the sweeep should be reset by the gate somehow if used that way when the pulses start it always start from low frequency

The voltage across the cell should stay at least as close to electrolysis voltage at all times.  The gate pulse should be set accordingly.  If the gate is too wide, the charge will dip too low and then you're starting all over again without results.

I’m not totally sure if the length of the wire is so important… also this long coils resonate at much lower frequency than 100kgz from what I remember from testing.. 

I believe there’s a contradiction between Stan words and what was shown

Meyer talk about bifilar all the time and this Vic’s founded  don’t seem to have any bifilar coil in it….

For me it’s more likely that the epg were the real used Vic than those

When applying a frequency above the self-resonant frequency of the coil supposedly than the signal is transported in the coil by capacitive effect meaning the coil kind of behave some like a capacitor above it’s resonant frequency… and what that mean?

Well it mean that when you apply a voltage to it it gets charged like a capacitor would… a simple coil would reverse its polarity immediately after it’s disconnected however a coilpacitor will be able to discharge the capacitive side of the coil first and only after that get the reversal of polarity… basically energy get consumed since the capacitance charge is opposite polarity to the inductor at the moment just where the current is interrupted…

Agreed.

The capacitor's dielectric material (in this case, water) and the conductive plates will have some inherent resistance, which is often referred to as equivalent series resistance (ESR). When you take this ESR into account, the capacitor can exhibit RC-like behavior to some extent.