Help Needed.
Started by unknown · · 25 posts · last reply 23 July 2019
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#1 ·
Hi, Anyone feel free to answer your opinion or fact here. I want your Thoughts and comments Please.
Please Dont be shy, Im really interested in what your point of veiw may be here. Everyone has their on thoughts so Please feel free to share yours with me.
Here is My question.
By the way, I dont feel comfortable Posting in a open forum but atleast this one is registered memebers only. Also, I have noticed that IonizationX doesn't show up in google results for me the way it use to stevie. Im sorta thankful for that, but anyhow. Here it goes!
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If you have an Window AC unit and it consumes 600 watts of electrical Power P. At 120 volts V, at 5 Amps I. Just a thought. Now on to the question.
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Question. If you have say 92 1.3volt rechargeable batteries in series, and the voltage was close to 120 volts. How long do you think the batteries would remain charged if producing 600 watts? I think each battery would produce 4 milliamps, I may be wrong.
How many amps do you think each battery would use? How long do you think they would remain in good health before voltage started droping?
Do you think you can divide the I Current draw as I just did say 40 Milliamps per battery? Or, does the current work some other way in this series configeration?
Please ALL COMMENTS Wanted!
Thanks! -
#2 ·
What if I used 13 9 volt batteries and got 117 volts to produces 600 watts.
Wouldn't that be under 400 Milliamps per cell?
Stevie, whats your thoughts? -
#3 ·
You'll have to use a lot more batteries than you're planning, to have an effective system. In series, each battery's Milliamps will be in the normal range, just as you suppose. However, the individual cells' voltage will start dropping almost immediately under load. The result will be that you get your 600 Watts only for a brief period. What you need to do is provide around 2 1/2 times the needed voltage, then run it through a regulator to output the 120. This way you'll stay at 120 for a while, even as the cells go down. Even then, you'll be lucky to run for a half hour, without parallel strings of batteries feeding the regulator. -
#4 · date not recorded
So, the 9v cell will drop when consuming 300ish milliamps after how long? Haw many must be in parallel to solve a 8 hour runtime? Let's go with 9 colts here. -
#5 · date not recorded
I think I would contract the manufacturer of the batteries and obtain the discharge specifications for the brand of battery used (something like car batteries rating ampere hours)
perhaps get so idea of battery sizing from Tesla 3 electric vehicles??
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#6 · date not recorded
A typical 9 volt battery is between 300mah and 500mah. So since this isn't actually field work here but "thoery only", let's just assume the battery is anywhere between 300 to 500 mAh, doesn't matter because it is the ideal we are after here And not firm solid legit perfectly crunched numbers. Let's crunch what we have and get a rough estimate.
With that being said. What would be your best bet using 13 batteries 9v. ? 5 seconds, 5 mins? 15 mins? And would it be benifittable to add 13 more in parallel. Let's assume we used 52, so that's 4 9v in parallel. -
#7 ·
how exactly is a solar panels built anyhow?
I have 5 panels, each is 37.5 volts and 8.5 amps.
If I connect 2 of the panels in parallel I get double the current production and the voltage remains the same.
But, If I connect 2 of my panels in series, the current production remains the same but the voltage doubles.
If I were to calculate the 600 watts directly from the utility pole, I would say I use 30 Milliamps at 20,000 volts, then onto the 240 pole transformer that consumes 2.5 amps, but my Window unit is 120 volts so I must have 5 amps.
I thought about powering the unit with a 12v battery at one time since everyone says thats the logical way to do it, but then I decided that 50 amps from that battery at such low voltage was not as appealing as the 120v DC using a H Bridge at 5 amps. But then I realized that If I could just somehow use 240 volts at 2.5 amps I would be more than willing to donate a amp or 2 for the heat loss of stepping it back down to 120, since the unit does operate on 120 volts.
I installed a new unit the other day and the rotor locked up, the locked roter amps was 108 amps at 240 volts. I realized that a locked moter was consuming over 25,920 watts!!! But I dont think anyone hardly noticed since I was only using 1296 Milliamps from the 20kvolt power line wire!
I still dont fully understand how my solar panel is built, Is it like one very long strip that produces 37 volts? and also, how you reckon it produces a whopping 9 amps of current at that 37 volts?
Anyone gave any thoughts to those 52 batteries in the question I ask above yet? Again, Your opinions are welcome, and No answer here has to be perfect. Get the Ideal in your head so I can be cleared up on this, then I will move on to the next step.
http://www.ti.com/tool/TMDSSOLARPEXPKIT
Thats a circuit I think is junk, But the Ideal is Legit, it has way to much computerized junk on it.
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#8 ·
https://michaelbluejay.com/batteries/9v.html
Which battery would you buy?
Think on it a while... And I understand most devices will not operate properly on lower voltages. -
#9 · date not recorded
What if I used 13 9 volt batteries and got 117 volts to produces 600 watts.
Wouldn't that be under 400 Milliamps per cell?
Stevie, whats your thoughts?
P=U*I
600= 117 * I
I= 5 amps. Not 400milliamps
So, your 9 volt batteries are sucked empty pretty quickly
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#10 · date not recorded
Tek is right about voltage drop. This happens when yr battery cannot deliver the proper amps.What if I used 13 9 volt batteries and got 117 volts to produces 600 watts.
Wouldn't that be under 400 Milliamps per cell?
Stevie, whats your thoughts?
P=U*I
600= 117 * I
I= 5 amps. Not 400milliamps
So, your 9 volt batteries are sucked empty pretty quickly
A 9 volt battery delivers about 250-300 mAh
to be able to provide 5 amps, you must use a couple of them in parallel. 20 strings of 13 batterys in series.
That works.
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#11 · date not recorded
how exactly is a solar panels built anyhow?
I have 5 panels, each is 37.5 volts and 8.5 amps.
If I connect 2 of the panels in parallel I get double the current production and the voltage remains the same.
But, If I connect 2 of my panels in series, the current production remains the same but the voltage doubles.
If I were to calculate the 600 watts directly from the utility pole, I would say I use 30 Milliamps at 20,000 volts, then onto the 240 pole transformer that consumes 2.5 amps, but my Window unit is 120 volts so I must have 5 amps.
I thought about powering the unit with a 12v battery at one time since everyone says thats the logical way to do it, but then I decided that 50 amps from that battery at such low voltage was not as appealing as the 120v DC using a H Bridge at 5 amps. But then I realized that If I could just somehow use 240 volts at 2.5 amps I would be more than willing to donate a amp or 2 for the heat loss of stepping it back down to 120, since the unit does operate on 120 volts.
I installed a new unit the other day and the rotor locked up, the locked roter amps was 108 amps at 240 volts. I realized that a locked moter was consuming over 25,920 watts!!! But I dont think anyone hardly noticed since I was only using 1296 Milliamps from the 20kvolt power line wire!
I still dont fully understand how my solar panel is built, Is it like one very long strip that produces 37 volts? and also, how you reckon it produces a whopping 9 amps of current at that 37 volts?
Anyone gave any thoughts to those 52 batteries in the question I ask above yet? Again, Your opinions are welcome, and No answer here has to be perfect. Get the Ideal in your head so I can be cleared up on this, then I will move on to the next step.
http://www.ti.com/tool/TMDSSOLARPEXPKIT
Thats a circuit I think is junk, But the Ideal is Legit, it has way to much computerized junk on it.
A solar panel is build out of small cells who are connected in serie.
I know as i have 40 panels here, pumping 90V dc into my MPPT which charges up my 20kw lit ion batterys
I use actually two mppt's.
I went for a 14S battery setup.
Tell me a bit more what your ideas are...What do you have and what goal have you set? -
#12 ·
Divide Ah by 10 to be a safe health of the used battery. So if you have 3000Mah for 1.2 volts it would be this sum you would not want to go over per hour.
3000mah or 3 amps/10 wouldnt want to use more than 300Mah constant flow over an hour period for 10 hours.
.350/10 This 9 volt battery can provide 35Ma for ten hours. Its understood this battery can not produce 350 in one hour, it would destroy it. But it can produce 35ma for 10 hours.
So, if I have 100 3000Mah 1.2 volt batteries. Again, I would then have 120 volts!
Consuming at a rate of 600 whats, thats 120 volts 5 amps!
If one did use 100 of these batteries to produce this, how much current would be consumed from each individual cell?
The Load Wants from each battery 50Ma. Because .50Ma X 100 Batteries is 5 amps.
The battery only wants to supply 300 Ma per hour for 10 hours, Since it is a 3000Mah battery.
But we're not asking each cell for 300 Ma in this situation, We are asking for 50Ma.
Please give this a second opinion. -
#13 ·
In my opinion, if you put a hundred batteries in parallel, the volts will be the same as a single cell, but the current will add up. Put the batteries in series, and the volts will add, but the current would only be what an individual cell can provide.
You can't get 600 Watts from 100 batteries unless you can get 6 Watts from a single battery. That's 4000 mA, continuous, with 1.5 Volt batteries. Until the voltage starts going down. -
#14 ·
100 battery,s in serie give the maximum amps of what 1 cell can give.
Batterys in parallel give the totall amps of all of them..
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#15 · date not recorded
Steve is right.
To achieve what you are thinking of, you need 100x100 batteries.
That's a lot! -
#16 ·
Thank you so much for solving this confusing iss for me! That's why I ask here, because 4 eyes and ears is better than 2 right?
A little twist here. My car battery is 600 cold cranking amps. That's a whopping 7200 watts of a jolt!
Let's say I want to take the 12 volts and move it's decimal point to the right 3 times. "12000" volts. And the 600 amps decimal point to the left 3 times, ".6".
Who here thinks the same power can create the same torq in horse power with the same wattage?
Move the decimal 4 times.
120,000 .06
Who here thinks a 120k moter that draws 60 milliamps can start a car?
If so, wouldn't the wire be smaller? Would this be possible without changing the size of the starter desined for 12 volts?
Comments and opinions please.
Thanks guys! And that is a ton of batteries in the last few post, but was very correct.
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#17 · date not recorded
Not sure where you're headed with this, but I can see a point of potential relevance. For instance, you could use the starter to drive a three phase alternator, chop the pulses so they squeeze together without overlapping, then hook it up to a WFC. If you're going to power the starter with HV, its wire size can't be too small, but doesn't have to BE small. The important factor is the HV has to be a pulse. You need to use a pulse forming technique, just as you would with an electrically produced EMP, except it would be in line (in the circuit), rather than fed to a coaxial ring antenna. So try chopping the HV and connect a metal funnel in the circuit going to the motor, for a biphasic shape resonance tuning effect. And be sure to use at least 20 feet of large gauge wire between the funnel and the motor, to allow the pulse to condense, before doing its magic in the motor. edit: Otherwise, you might radiate a pulse anyway, frying the electronics in your car and everything else within two or three blocks.
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#18 ·
Since this is a new page, here's a quote of the message I responded too:Thank you so much for solving this confusing iss for me! That's why I ask here, because 4 eyes and ears is better than 2 right?
A little twist here. My car battery is 600 cold cranking amps. That's a whopping 7200 watts of a jolt!
Let's say I want to take the 12 volts and move it's decimal point to the right 3 times. "12000" volts. And the 600 amps decimal point to the left 3 times, ".6".
Who here thinks the same power can create the same torq in horse power with the same wattage?
Move the decimal 4 times.
120,000 .06
Who here thinks a 120k moter that draws 60 milliamps can start a car?
If so, wouldn't the wire be smaller? Would this be possible without changing the size of the starter desined for 12 volts?
Comments and opinions please.
Thanks guys! And that is a ton of batteries in the last few post, but was very correct. -
#19 ·
I am also curious what your ideas are.
To turn on a car, your electromotor needs torque.
If you use a high rpm e motor and a gear ratio that goes from 120k rpm to 100 rpm, you might even make the engine turn.....
I want to see a video of that......
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#20 ·
Torque is good, but 7200 watts of power is 9.6 horse power since there's 745 watts In 1 hp, right?
I want that same jolt of hp at 1,200,000.00 volts .006 ma!
I recently researched how to decrease voltage using voltage splitters similar to a voltage divider circuit.
Does anyone here have any ideal what size capacitors it would take to store this type of voltage and charge?
It took me a while to realize that just because you split the or step down the voltage on a DC circuit doesn't mean you have a loss.
I'm wondering about those helicopters with those crate cables that's zapping people that don't wear gloves. Its self generated and there.
Steco I'm having a difficult time with some 37.5 volt solar panels I've purchased. I can put 3 batteries in series and draw from only 1, and I've came to the conclusion I only need to parallel up on just the battery I'm drawing from and not the other 2. But also, I'm wanting to avoid the low 12 volts all together. -
#21 · date not recorded
Using batteries like that as a voltage divider will only work if they all have the same internal resistance, overall health, and draw. Once even one battery thinks it's fully charged, the divider network will fail, placing up to full voltage on the paralleled load.
Energy storage in capacitors is measured in Joules (W/second). For instance, Moray's walnut sized 'sparking condenser' would store 5,000 Joules at 10 kV.
HV motors are a special area of technology. One model has a rotor with radial corrugations. For cooling, it's advisable to have a number of holes in the ridges. To avoid complications, it's probably best to learn to use what's available to us. A solar panel can power some motors directly, such as a water pump or automotive engine cooling fan. -
#22 ·
If I had 1 12 volt battery I would need 600 or so watts from that battery.
Could anyone Confirm to me this Please. Beacause I am not certain.
If I use 2 batterys, both 45 amp hours per battery, would this cut the wattage from one of the batteries in half, say 300 watts instead of 600?? and 300 also from the second battery to total up to 600 watts?
Thanks! -
#23 ·
Your amperage values are correct. But keep in mind that lead/acid batteries are a defective technology. Internal damage will start to occur after discharging more than 15% of the rated capacity, which is just under seven A/hr with yours. After that, they'll have less capacity when recharged, and so on, until they have to be replaced. So make sure the power coming in from the solar panels is adequate to handle most of the load, to prevent excessive drain on the batteries. -
#24 ·
Thank you, I'm sorta backwards when it comes to this. I have severe dislexia.
I must ask, how many batteries of this great size must I need to do this at a healthy rate? Also, if I may..
And I know this sounds a bi
t crazy and probly somewhat difficult for one to understand mainly because this is only 2019, but here I will state. And, just a gentle wonder here.
Let's say I have access to 1,000,000 12v micro cells in a reasonably sized container, that has a somewhat usefull mAh rating.
Would I just divide the 600 watts by the million cells to get my current draw rating? And how long would they last before I had to connect the solar charger to my nano cell box to recharge them? Each cell has a trip, if it is at fault it disconnects an triggers a light across it. -
#25 ·
Thank you, I'm sorta backwards when it comes to this. I have severe dislexia.
I must ask, how many batteries of this great size must I need to do this at a healthy rate?
I have a deep cycle marine battery which is rated at 725 cranking Amps. The label also says 115 A/hr @ 20 hr. So that means you can safely get just over five Amps out of it on an ongoing basis. For 600 Watts, you would need ten of these large, heavy batteries.
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