tur55

We don't have a particle accelerator.
What are you talking about?

The statement "demystification" is too loud.
There are no formulas that can be checked and recalculated.
You can check your words (text), if only your installation gives a volume of Brown gas greater than Faraday electrolysis.That is, according to the final result. With the same size of the fuel cell area and the volume of water used.
Formulas also allow you to check at each stage. Starting from the generation scheme -> VIC -> fuel cell

Well, as I stated in the other post, the voltage in the cell is directly proportional to the current passing thru it. No matter how many turns your bifilar has, if it does not have the capability to feed many amps to your cell, you wont have high voltages at your cell, unless the resistance of your cell is huge (with the cell beign small). My cell has 100 Ohms resistance, I need 10 amps peak to have 1kV in it. In my case, if I had 1000t bifilar with awg35 wire, I would never reach kV in my cell, I can achieve with kV with 200t, awg23, but is pure electrolysis. If 100V is applied to a 100Ohm load, you'll always have 1amp, you'll never get to restrict the current without lowering the voltage, this is ohms law. You cannot apply 100V to a 100ohms load and have only miliamps, and it does not have anything to do with the frequency, you can sweep you cell from DC to 1Ghz, the frequency response is flat.

Make the cell resistance 200 Mega Ohms!
And when a voltage of 2 Kilo Volts is applied, you will have 2000 divided by 200000000 equal to 0.00001 amperes

Почему тут тихо!!
Куда девался Себосфато?

Radiant_1.  that's how to explain it. With graphs, pictures, formulas. Your naked text can be interpreted in an infinite number of ways.

His demo cell (Lawton replication) was resonant and arguably non-faradic...but how the hell could he supply water vapor and ozone directly to a spark plug voltage zone (his very last version) and have a singular dissociation and then explosive event at the end, and it have any of the stuff claimed to be going on in the Lawton replication happen?
Hmm, I wonder what he meant by Voltage "Intensifier" Circuit...or the comment "current is not delivered or made to flow....in the standard way"?

And on my channel, all the formulas that explain what is happening in the Meyer cell are presented.

Maxwell's law works.
https://en.wikipedia.org/wiki/Maxwell%27s_equations

Exactly Ampère's circuital law
https://en.wikipedia.org/wiki/Ampère%27s_circuital_law

These are just words, they are not confirmed by calculations, and calculations are not confirmed by experiments.
Having a successful experiment without calculations does not guarantee that the process went exactly as you describe in words.
There is no way to verify your words if you have not provided calculations.Moreover, there is no way to test the experiment if you do not provide calculations.
By what figures can you prove that you had the Meyer process and not the Faraday electrolysis?
I am skeptical of your words.
I think you got a Faraday pulsed electrolysis.

you also will have zero volts across the water in that way

Equivalent circuit of a capacitor - fuel cell.
Make the resistance Re = 200 Mega ohms and you can supply 2 kilo volts.
Where Re is the insulation resistance
Circled in blue in the picture

Quote from: tur55 on September 03, 2024, 18:34:44 pm

Quote from: uziao on September 02, 2024, 22:36:38 pm

If you have low current at the cell, the voltage at the cell will be Current (I) x Cell resistance (R).

For an 100Ohms cell, you need 1 amp to give you 100V.

Someone need to demonstrate how to violate ohms law first to assure that he had high voltage at the cell.

It is impossible to reach kV ratings in an 80Ohms cell using miliamps... And there is no phase shift between current and voltage at the cell...

You are thinking correctly.
Watch Ravi's channel where he shows the white coating on the pipes. This plaque, or rather its resistance, increases the voltage at low current.
There are about 5 methods to reduce the current to 0.001 ampere, but they must be used all together and synchronize their work with each other

You are right, I already saw that at Ravi's channel, but all of Stans tubes have no white coating on it, so he must be using another technique...

Another point is that we cant use anything between the tubes and the water as insulator. A capacitor polarization occurs at the dieletric. Our aim here is to have displacement charges at the water, which should be our "dielectric". Anything in between will be charged instead of charging the water.

Water cannot be a dielectric all the time. Since it is saturated with ions. And therefore becomes a conductor.
In other words, water changes its physical properties 'dielectric-conductor'.
Stan Meyer said in one of the videos that the longer a fuel cell runs, the better it works.
It can only be one thing, calcium oxide buildup on the electrodes

If you have low current at the cell, the voltage at the cell will be Current (I) x Cell resistance (R).

For an 100Ohms cell, you need 1 amp to give you 100V.

Someone need to demonstrate how to violate ohms law first to assure that he had high voltage at the cell.

It is impossible to reach kV ratings in an 80Ohms cell using miliamps... And there is no phase shift between current and voltage at the cell...

You are thinking correctly.
Watch Ravi's channel where he shows the white coating on the pipes. This plaque, or rather its resistance, increases the voltage at low current.
There are about 5 methods to reduce the current to 0.001 ampere, but they must be used all together and synchronize their work with each other

I don't agree. Current is the number of electrons through a cross section per unit time. Stanley prevented the current, that is, made it less than 1 ampere.
For Faraday electrolysis, electrons are useful, so the current there is up to 20 amperes and higher. For Meyer's voltrolysis, electrons are harmful, so it was made at less than 1 ampere

Hello every one.

Many years, i am running this forum, but there are not so many people are interested in the topics here.
Shall i close the forum, or shall i keep it open?


Regards
Steve

Hold on! After a dark night, there is always dawn.
Now small and medium -sized firms enter the hydrogen market.
When large companies come in, you will need your forum as a place of training.