Resonant Cavity - The truth about amp loading! - Discussion
Started by unknown · · 11 posts
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#1 · date not recorded
Some people saying that stan states that per VIC unit from the dune buggy the amp draw at resonance or out of it will be few milliamps.
That is not true and lets discuss that in fair way.
Here is some start point:
Look into voltage amplitude control, There is an adjustable linear voltage regulator that can handle about 1 or 1.5 amp ALONE, right?
Why did Stan put it coupled with 2n3055 transistor?
The answer is easy:
To work ABOVE this load (from 2 to about 6 Amps at maximum).
Lets talk about it and make this forum back to live again. -
#2 ·
The simple fact is, amps are going to jerk the water molecules back and forth. Is this what Stan was doing? If he used a rotating electric field, as a particle accelerator, then amps would play a role. The moving water molecules would dissociate on impact with an electrode or other molecule. But if the molecules are to remain stationary, so that they can be stretched apart with potential pulses only, then amps would have to be minimized. Was he doing one thing and saying something else? -
#3 ·
There is no proof or evidence about this.
No one tested the VIC and cell from the dune buggy.
If it draws almost nothing what can explain the lm317 coupled to 2n3055 in each VIC card for the amplitude regulation?
Thats a fact and my point of view.
To get high voltage (if there is any used) it requires power (Pin=Pout) - no magic.
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#4 ·
To get high voltage (if there is any used) it requires power (Pin=Pout) - no magic.
Then that's your answer. -
#5 ·
Amps are needed to produce the magnetic field which powers the transformer. Minimal current at the cell doesn't mean there is no draw at the input to the circuit. The key is to get rid of the amps in the output. A resonant choke will only pass current at its resonant frequency. With even a little detuning, the amps will quickly fall off and diminish. A choke which completely blocks the current will still pass a high voltage longitudinal pulse. (According to Farnsworth.) What we should be looking at is what kind of energy is being applied to the cell? -
#6 · date not recorded
mAN THE QUESTION IS TO A CAPACITOR TO GET CHARGED YOU MUST DO WHAT? force? work right? -
#7 · date not recorded
Yes your point of view is correct, but i belive that minimum current Stan stated is across the cell, even at 0.025A over 2KV will draw 50W
that represent a primary load of 4.17A @ 12V.
But some people used to say that this load is as primary and this is clear on the patent : Load across the cell.
Stan stated it even in new zeland house meeting video.
39:22 to 40:00 You can hear it from Stan's words:
[youtube]https://www.youtube.com/watch?v=yGqCaVFWIWQ[/youtube]
The pictures and the data collected by Dynodon is very precious! Thanks to him again and again! -
#8 · date not recorded
See the video and tell me what you think. -
#9 · date not recorded
Sebosfato im not saying this is conventional electrolysis. Just talking about (primary) battery load. -
#10 · date not recorded
electrotek see what happens on LC circuit at resonance:
http://www.play-hookey.com/ac_theory/randr/ac_lc_series.html
When XL=Xc ...
Z is ZERO, no reactance.
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#11 · date not recorded
electrotek
When XL=Xc ...
Z is ZERO, no reactance.
How remarkable. Does this mean a choke will pass current at its resonant frequency? What did I just say?
Beam me up, Scottie ...
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