(Mur)
Mu Atomic Mass Ratio
Where it is first named
Electron (E) = 1 Proton (P) - 1Mu Hydrogen Atom: IE = IP - IMu Oxygen Atom: 8E = 8P - 8Mu Atomic Mass Ratio (Mur) of Water (2H X 1Mu) plus (1 Oxy. X 8 Mu) = 10 Mu's See Appendix (B) Note (2)
How it is written
- (Mur) 3×
Drawings 3
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Thus, One gallon of Water contains 1.6691 lbs. of Hydrogen · Application Notes
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Thus, One gallon of Gasoline equals 5.61 lbs/gal. 5.61 lbs/gal. times .117 = 0.6561 lbs of Hydrogen / Gasoline gal. · Appendix A
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Thus, One pound (lb) of Natural Gas contains .28 lb of Hydrogen Atoms. · Appendix 3
Where it is named · 3
Application Notes 1×
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Mu Atomic Mass Ratio (Mur)
Electron (E) = 1 Proton (P) - 1Mu Hydrogen Atom: IE = IP - IMu Oxygen Atom: 8E = 8P - 8Mu Atomic Mass Ratio (Mur) of Water (2H X 1Mu) plus (1 Oxy. X 8 Mu) = 10 Mu's See Appendix (B) Note (2)
Appendix A 1×
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Mu Atomic Mass Ratio (Mur)
I Electron = 1 Proton - 1 Mu Hydrogen Atom: IE = 1P - 1 Mu Carbon Atom: 6E = 6P - 6 Mu Atomic Mass Ratio (Mur) of Gasoline: (8 H X 1Mu) plus (1 Oxy 6Mu) = 68 Mu's See Appendix (B) Note (2)
Appendix 3 1×
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Mu Atomic Mass Ratio (Mur)
1 Electron (E) = 1 Proton (P) ... 1 Mu Hydrogen Atom: 1 E = 1P ... 1Mu Carbon Atom: 6 E = 6P ... 6 Mu Atomic Mass Ratio (Mur) of Natural Gas: (12H x 1 Mu) plus (5C x 6 Mu) = 42 Mu's See Appendix (B) Note (2)
