uziao

Not my latest but you get an idea.
Yellow: input
Blue: voltage on the cell.

The current is identical to voltage, pure electrolysis. This waveform is just the result of the current being modulated by the inductors (inductor modulator as said by Stan), multiplied by the resistance of the cell.

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he even needed stainless steel enameled wire with high resistance in order to match the transformer to the injectors

This is not the only important property of this wire (430fr), and most people are ignoring something VERY important about that.

Remember, when you use resistive element, the power is dissipated on it...

Calculate the power loss on that resistance and tell me what do you see...

You are right, it takes little power to convert some microdroplets of water into hydrogen, thats the beauty of the small injectors, and, according to stan, you'll end up ionizing the hydrogen as a "side effect" after the water dissociation. The injector electrode resistance needs to be equal to the coils resistance to ensure max power transfer. When you make the electrodes small, the resistance goes up, it means that the ratio V/I increases and you have more voltage than current.
You cant do the same with some 4 inch long cells, it takes much more power and much more current, mine has about 100ohms resistance. If you put 10kV in a 100ohms resistance, you'll end up with 100A. If you put 10kV in a 10kohms resistance, you'll end up with 1A.

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Yeah, if you do not have enough voltage to start electrolysis, you have no current flowing

You do have current flow without electrolysis,  until the "capacitor" charges up.

You can try it with a big cell and you can observe it easily. 

If it looks to you irrelevant, it is up to you, but there is more interesting things happening in the cell that some people do not talk about or is just ignoring.

Is called displacement current, it is the charge that builds up before the conduction current kicks in.

I'm really confused right now, are we trying to replicate Meyers high voltage, high frequency aparatus, or are we trying to prove some low voltage stuff that has nothing to do with meyer? If you make your cell bigger, you'll have less resistance between the plates and more current will flow for the same voltage. Thats why he moved to the high resistance injectors, he even needed stainless steel enameled wire with high resistance in order to match the transformer to the injectors. What im trying to say, is that the only way to achieve high voltage, with low current in a water bath, is to make the electrodes very small. The cells impedance will never change, even when in resonance, because above 2v, it is a resistor. You cant restrict current in a resistor, you cant violate ohms law, you cant make voltage go up and amps go down in a resistor, the only way is if you make the resistance high enough, making it small enough.

Well, I made this test over and over. From DC to 1GHz, it acts as a resistor, with voltage in the cell beign Rcell x Icell. No voltage/current returning when switching off signal, only resistance (voltage and current are linear functions). The cell can hold aprox. 1,5[V] before electrolysis begin and thats all.

As Stan said:

Water now becomes part of the Voltage Intensifier Circuit in the form of "resistance" between electrical ground and pulsefrequency positive-potential ... helping to prevent electron flow within the pulsing circuit (AA) of Figure 1-1.

I dont think so.

2 plates spaced by a water dielectric behaves like a resistor. You can frequency sweep it from DC to 1 GHz and see no changes in voltage/current/gas generation, thats not the behaviour of a capacitor used in a LC tuned circuit. Stan even says that in the WFC memo, that the water will become part of the circuit in form of resistance.
When you energize this kind of reactor, the voltage that develops across it, is the product of RxI, nothing more, and you get pure electrolysis only.

All you can do is increase the reactor impedance, to get a higher V/I ratio, and therefore rip the water molecule with less current. You cannot reach resonance with an inductor in series with a resistor.

In my opinion, this voltage ripping the molecule apart, only works in a very small scale, thats why he moved to the injectors.